What happens when a raise statement is encountered in a function?

When a raise statement is encountered in a function, it triggers an exception, which causes the function to exit immediately. This means that none of the subsequent lines of code within that function will be executed after the raise statement. The function does not return any value in the traditional sense; instead, it generates an exception that can be caught and handled by surrounding try-except blocks or propagated up the call stack.

In the context of raising exceptions, the intent is to signal that an error or an unexpected condition has occurred. When the raise statement is executed, the program's control flow is altered, and the normal execution of the program is interrupted to handle the exception. Therefore, this understanding aligns perfectly with the answer, which states that the function exits with no return.

By contrast, the other options suggest behaviors that do not accurately represent how exceptions function in programming. The following clarifications illustrate why the remaining choices do not align with the mechanism of the raise statement. For instance, stating that the code continues executing to the next line misrepresents the flow of control, as the raise statement halts execution. Similarly, the idea that the raise exception becomes printed immediately or that it returns a specific value such as -1 does not capture the essential nature of an